Hello!The answer is:[tex](g\circ f)(0)=-216[/tex]Why?To composite functions, we need to evaluate functions in another function(s), for example:Given f(x) and g(x), if we want to calculate f(x) composite g(x), we need to evaluate g(x) into f(x).So, we are given the functions:[tex]f(x)=2x-6\\g(x)=x^{3}[/tex]And we are asked to calculate g(x) composite f(x), and then evaluate "x" to 0, so, calculating we have:[tex](g\circ f)(x)=g(f(x))\\\\(g\circ f)(x)=(2x-6)^{3}[/tex]Now that we have the composite function, we need to evaluate "x" equal to 0, so:[tex](g\circ f)(0)=(2x-6)^{3}\\\\(g\circ f)(0)=(2*(0)-6)^{3}=(0-6)^{3}=-6*-6*-6=-216[/tex]Hence, we have that:[tex](g\circ f)(0)=-216[/tex]Have a nice day!