1) What is the solution to the system of equations?-2x + y = -53x – 2y = 12A) (3, 1) B) (6, 3) C) (-2, -9) D) (-2, -1) 2) y = x + 22x - y = -4 Solve the system of equations using substitution.A) (-2,-4) B) (-2,0) C) (-6,-4) D) (-6,8) 3) x = y + 42x - 3y = -2 What is the solution to the system of equations?A) (6, 10) B) (9, 5) C) (10, 6) D) (14, 10) 4) x + 2y = 33x - 2y = 5 What is the solution to the system of equations?A) (4, 3.5) B) (2, 12)) C) (2, -1) D) (12, 2) 5) Use the graph method to solve the system of linear equations:2x + y = 3 and x + y = 3A) (-1.5, 0) B) (0, -1.5) C) (0, 3) D) (3, 0) 6) y = −13 x + 2y = x + 2 What is the solution to the system of equations?A) (0, 2) B) (2, 0) C) (-1, 3) D) (0, -2) 7) x = y - 3x + 3y = 13 What is the solution to the system of equations?A) (1, 4) B) (4, 1) C) (7, 4) D) (2.5, 5.5) 8) How many solutions can be found for the system of linear equations represented on the graph?A) no solution B) one solution C) two solutions D) infinitely many solutions 9) Which graph represents the solution for the equation 12x - 1 = -x + 2?A) A B) B C) C D) D * Hover over answer image to enlarge10) x + 3y = 5-x + 6y = 4 Solve the system of equations.A) x = 1, y = 2 B) x = 2, y = 1 C) x = 1, y = 1 D) x = 0, y = 2 11) Find the solution to the system of equations graphed here.A) (-1, -3) B) (1, -3) C) (1, 3) D) (3, 1) 12) How many solutions can be found for the system of linear equations represented on the graph?A) no solution EliminateB) one solution C) two solutions D) infinitely many solutions 13) Use the graph method to solve the system of linear equations:y - x = -2 and 2x + y = 7A) (0,7) B) (2,0) C) (3.5,0) D) (3,1) 14) Identify the solution for the system of equations graphed here.A) (1, 1) B) (-1, 1) C) (1, -1) D) (-1, -1)

Answer:1) C [tex]s=\left \{ (-2,-9) \right \}[/tex] 2) (-2,0) 3)[tex]S=\left \{ (14,10) \right \}[/tex] 4) [tex]S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}[/tex] 5) c )S={(0,3)} 6) (0,2) 7) [tex]A) S=\left \{ \left ( 1,4 \right ) \right \}[/tex] 8) Missing graph 9) Vertical line (check below) 10) B 11) Step-by-step explanation:1) Solving by the Addition/Elimination Method. Firstly, let's reduce one variable by making some algebraic adjustments and then adding it up:[tex]\left\{\begin{matrix}-2x&+y&=5 *(3)\\ 3x&-2y&=12 *(2)\end{matrix}\right.\Rightarrow \left\{\begin{matrix}-6x&+3y&=15  \\6x&-4y&=24 \end{matrix}\right.\Rightarrow -y=9\Rightarrow y=-9\Rightarrow 6x-4(-9)=24\Rightarrow 6x+36=24\Rightarrow 6x=-36+24\Rightarrow 6x=-12\Rightarrow x=-2\Rightarrow s=\left \{ -2,-9 \right \}[/tex]2) Solving by Substitution Method. Where y=x+2 is plugged in the 2nd equation. [tex]\left\{\begin{matrix}y =&x+2 & \\ 2x-y &=-4 & \end{matrix}\right.\Rightarrow 2x-(x+2)=-4\Rightarrow 2x-x-2=-4\Rightarrow x=-4+2\Rightarrow x=-2\: and\: y=-2+2\Rightarrow y=0\Rightarrow S=\left \{ \left ( -2,0 \right ) \right \}[/tex]3) Solving it, again, by the Substitution Method due to the I equation form:[tex]\left\{\begin{matrix}x=y+4& \\ 2x-3y=-2& \end{matrix}\right.\Rightarrow 2(y+4)-3y=-2\Rightarrow 2y+8-3y=-2\Rightarrow y=10\: \: x=10+4\Rightarrow x=14\Rightarrow S=\left \{ (14,10) \right \}[/tex]4) By the Addition Method [tex]\left\{\begin{matrix}x+2y &=3 \\ 3x-2y &=5 \end{matrix}\right.\Rightarrow 4x=8\Rightarrow x=2\Rightarrow 2+2y=3\Rightarrow 2y=1\Rightarrow y=\frac{1}{2}\: S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}[/tex]5) To use the graph method to solve the system of Linear equations is possible by graphing each equation on the Cartesian Plane.Check the graph below, this system has only one solution.c)S={(0,3)}6) Solving y=-1/3x+2 y=x+2(Check the graph below)A) A) (0, 2)7) Solving by Substitution Method:[tex]\left\{\begin{matrix}x=y-3 & \\ x+3y=13& \end{matrix}\right.\Rightarrow y-3+3y=13\Rightarrow 4y=13+3\Rightarrow 4y=16\Rightarrow y=4\: \: \\x=4-3\Rightarrow x=1 \\S=\left \{ \left ( 1,4 \right ) \right \}[/tex]8) Missing graph9)[tex]\frac{1}{2}x+x=1+2\Rightarrow \frac{3}{2}x=3\Rightarrow x=2\\ S=\{2}\\[/tex]Check the graph below its answer10) Solving by the Addition Method[tex]\left\{\begin{matrix}x+3y=5 & \\ -x+6y=4& \end{matrix}\right.\Rightarrow 9y=9\Rightarrow y=1  \: \: And \: \: x+3(1)=5\Rightarrow x=5-3\Rightarrow x=2\\S=\left \{ \left ( 2,1 \right ) \right \}[/tex]11) Sorry, missing graph for the question.12) Sorry, missing graph for the question.13) D Check the graph below14) Sorry, missing graph for the question.