The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

Answer:Point used by Harold was:(7, 0)Step-by-step explanation:Given that Equation of linear function used by Harold:[tex]y = 3(x - 7)[/tex]We know that linear equation in point slope form can be represented as:[tex]y - y_1 = m(x - x_1)[/tex]Where [tex](x_1,y_1)[/tex] are the coordinates of a given point.[tex]m[/tex] is the slope of line.Formula for Slope, m is given as:[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the two points on the line.If slope and a point with coordinates [tex](x_1,y_1)[/tex] is know, the equation of a line can be represented in linear form as:[tex]y - y_1 = m(x - x_1)[/tex] ....... (1)Now, the given equation is:[tex]y = 3(x - 7)[/tex]Re-writing the equation with a slight modification:[tex]y-0 = 3(x - 7)[/tex]Now, comparing the above equation with equation (1):We get that:[tex]x_1=7\\y_1=0[/tex]So, the point used by Harold is (7, 0).