What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x/3−1 ? Enter your answer in the box.
Accepted Solution
A:
y = x/3 - 1....the slope here is 1/3. A perpendicular line will have a negative slope. All that means is flip the slope and change the sign. So our perpendicular line will have a slope of -3....see how I flipped 1/3 making it 3/1...and then I changed the sign...making it -3/1 or just -3
y = mx + b slope(m) = -3 (4,2)...x = 4 and y = 2 now we sub into the formula and find b, the y int 2 = -3(4) + b 2 = -12 + b 2 + 12 = b 14 = b